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1 year ago

Help please how do u solve this

Mathematics

1 answer:

Leokris [45]1 year ago

3 0

Answer: 37/12

Step-by-step explanation:

11/12+2 1/6=

2+11/12+(1*2)/(6*2)=

2*12/12+11/12+2/12=

24/12+13/12=37/12

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19) Suzy is covering a wall with wall paper. If theshaded part of the figure below represents herwall, how much wallpaper should

lara [203]

12 square's of wallpaper. Because the shaded part has 4 square's down and 3 square's across so 3×4=12

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3 years ago

How can i prove this property to be true for all values of n, using mathematical induction.

chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

$\implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6}$

$\implies{ \frac{1(2)(3)}{6} }$

$\implies{ 1}$

Therefore, it is true for the first part.

In the second part we will assume that,

$\: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }$

and we will prove that,

$\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}$

$\: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}$

<u>Henceforth, by </u><u>using </u><u>the </u><u>principle </u><u>of </u><u> mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n</u>.

_______________________________

<em>Please scroll left - right to view the full solution.</em>

8 0

2 years ago

What measure of center best represents the data set? Drag and drop the correct answer into the box. Data Set Best Measure of Cen

ella [17]

The measure of center best represents the data set is Mean or Median.

Given

Data Set Best Measure of Center {27, 29, 26, 28, 25}.

The mean is the average of a set of data.

The mean is found by finding the sum of the data and then dividing the sum by the number of data.

<h3 />

The mean of the given data set is;

$\rm Mean = \dfrac{27+29+26+28+25}{5}\\\\Mean =\dfrac{135}{5}\\\\Mean =27$

Arranging the data set in the ascending order

{25, 26, 27, 28, 29}

The median is defined as the middle value of the given data set.

The median of the data set is 27.

Hence, the measure of center best represents the data set is Mean or Median.

To know more about mean and median click the link is given below.

brainly.com/question/1363341

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2 years ago

Find the expression for the area of the figure. Give your answer as a simplified radical.

Marizza181 [45]

Answer:

Step-by-step explanation:

Area of rectangle= length × breadth

Area of figure

$= ( \sqrt{15x}) ( \sqrt{10x} ) \\ = \sqrt{(10x)(15x)} \\ = \sqrt{150 {x}^{2} } \\ = \sqrt{6(25 {x}^{2}) } \\ = (\sqrt{6} )( \sqrt{( {5x})^{2} } ) \\ = ( \sqrt{6} )(5x) \\ = 5x \sqrt{6}$

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3 years ago

Please help asap question eight *

bearhunter [10]

Answer:

1.3

Step-by-step explanation:

When we have y = mx + b, where m is the slope and b is the intercept in the y function, we have an equation of the slope.

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3 years ago

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