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1 year ago

Which theorem, term, or corollary is represented by the picture?

Mathematics

1 answer:

Over [174]1 year ago

8 0

The triangle is an Corollary 1 to the isosceles triangle theorem.

Given that,

In the picture we have a triangle,

We have to find which triangle is it.

From the triangle,

The 2 sides are equal and the 2 angles are also equal.

So, The triangle is an Corollary 1 to the isosceles triangle theorem.

According to the isosceles triangle theorem, if two triangle sides are congruent, then the angles across from those sides are likewise congruent.

An isosceles triangle is one with two sides that are the same size and a third side that is a different size.

Therefore, The triangle is an Corollary 1 to the isosceles triangle theorem.

To learn more about triangle visit: brainly.com/question/2773823

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Its all in the picture please help as soon as possible

AVprozaik [17]

The first angle given is not needed. it is extra info.
so to start off you need to see that it is a subtraction problem. it is angle BEF minus angle GEF
90 degrees minus 39 degrees then it is all math.
angle BEG = 51 degrees

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2 years ago

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Just curious, I want to see who can get this. tooooootttalllllly know it already

Aneli [31]

Answer:

yea that makes sense

It literally tells you how to do it

Is it some kind of proof tho? Like the math makes sense but like I've never heard of this thing.

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2 years ago

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

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2 years ago

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Leno4ka [110]

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Step-by-step explanation:

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