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2 years ago

6

Out of 4a>-5 -5<4a -4a<5 5<-4 which ones have the same answer?

1 answer:

diamong [38]2 years ago

7 0

The first two equations are the same. They both mean 4a is greater than -5.

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A salesperson set a goal to earn $3,000 in July. He receives a base salary of $1,200 per month as well as a 10% commission for a

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Well, the commission should total $1,800. This is one tenth of what he sells, so he must sell $18,000 value of merchandise.

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How do you Graph y=-3/5x+6

dangina [55]

Let's pick two points on the line, the y-intercept, and the x-intercept. These are the points at which x=0, and y=0.

When x=0:
$y=-3/5x+6
\\y=-3/5(0)+6
\\y=6$

So one point is (0,6)

When y=0:
$y=-3/5x+6
\\0=-3/5x+6
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So mark the points (0,6) and (10,0) on a pair of axes, and draw a straight line between them, and past them to infinity. This is a graphing of the line y=-3/5 x + 6

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2 years ago

Which of the following statements about observational studies is true? A census is always preferable to a sample survey since it

Rashid [163]

Answer:c

Step-by-step explanation:

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3 years ago

Solve the equation<br> 2 x 1 1/2 = 46

AleksAgata [21]

Answer:

46

Step-by-step explanation:

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2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

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3 years ago

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