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pychu [463]
1 year ago
9

Give the following equations determine if the lines are parallel perpendicular or neither

Mathematics
1 answer:
GaryK [48]1 year ago
5 0

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

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a. Bill's maximum speed is 8 m/s

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<h3>Methods used to calculate speed and distance traveled</h3>

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Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

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c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

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