Step-by-step explanation:
as we have a point and the slope, we can start with the point-slope form and then transform.
the point-slope form is
y - y1 = a(x - x1)
(x1, y1) being a point on the line, a being the slope.
the slope-interceot form is
y = ax + b
a being the slope again, b being the y-intercept (the y value for x = 0).
so, we have
y - -5 = 5/2 × (x - -4)
y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10
y = 5x/2 + 5
or
y = (5/2)x + 5
and this is already the slope-intercept form. all done.
Answer:
6k^3(2 - 5k)
Step-by-step explanation:
12k^3 - 30k^4
Factor out 6k^3
6k^3(2 - 5k)
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
Answer:
Its 4/5
Step-by-step explanation:
you divisde 3/5 into the 5th. HOPE THAT HELPED!
Answer:
Perpendicular
Step-by-step explanation:
-2x+3y=-1
6x+4y=4
----------------
3y=-1-(-2x)
3y=-1+2x
3y=2x-1
y=2/3x-1/3
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4y=4-6x
4y=-6x+4
y=-6/4x+4/4
y=-3/2x+1
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2/3 and -3/2 are negative reciprocals, therefore, they are perpendicular.
