Casey is 18 years old and Ralph is 3 years old.
Step-by-step explanation:
Let,
Age of Casey = x
Age of Ralph = y
According to given statement;
x = 6y Eqn 1
In two years
x+2=4(y+2)
x+2=4y+8
x = 4y+8-2
x = 4y+6 Eqn 2
Putting value of x from Eqn 1 in Eqn 2

Dividing both sides by 2

Putting y=3 in Eqn 1

Casey is 18 years old and Ralph is 3 years old.
Keywords: word problems, substitution method
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The greatest whole humber like that is 987654321
Answer:
C
Step-by-step explanation:
C is the answer because a1=7 , d=-4 and so it's
an=an+(n-1)d
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)