Question

To the nearest tenth, what is the distance between the points (1, –2, 5) and (0, 7, –4)?

Answer 1

Answer:

The distance is $12.8\ units$

Step-by-step explanation:

we know that

The formula to calculate the distance between two points is equal to

$d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}+(z2-z1)^{2}}$

we have

$A(1,-2,5)\\B(0,7,-4)$  

substitute the values

$d=\sqrt{(0-1)^{2}+(7+2)^{2}+(-4-5)^{2}}$

$d=\sqrt{(-1)^{2}+(9)^{2}+(-9)^{2}}$

$d=\sqrt{1+81+81}$

$d=\sqrt{163}\ units$

$d=12.8\ units$