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oksano4ka [1.4K]
1 year ago
15

Maxine and her daughter are going grocery showing after she gets off work. Maxine sees that apples are $0.25, while bananas are

$0.79. She has $2.50 to spend on apples, x, and bananas. y. Write the equation, in standard form that represents her situation.
HELP ME PLEASE
Mathematics
1 answer:
Butoxors [25]1 year ago
3 0

Her situation can be modeled by the linear equation (in standard form):

x*$0.25 + y*$0.79 = $2.50

<h3>How to write the equation that represents her situation?</h3>

The variables that we will use here are:

x =  number of apples that she can buy.

y = number of bananas that she can buy.

We know that she has $2.50 to spend, that each apple costs $0.25 and each banana costs $0.79, then the cost of the x apples and y bananas is:

x*$0.25 + y*$0.79

and that must be equal to the amount she has to spend, then we can write the linear equation:

x*$0.25 + y*$0.79 = $2.50

That is the linear equation in standard form that represents her situation.

Learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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<u><em>Answer</em></u>

x=\frac{11}{3}

<u><em>Explanation</em></u>

Based on the given conditions, formulate:: y=3

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Rearrange variables to the left side of the equation: 6x=25-3

Calculate the sum or difference: 6x=22

Divide both sides of the equation by the coefficient of variable: x=\frac{22}{6}

Cross out the common factor: x=\frac{11}{3}

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On a map, the distance from Happy Hill Park to Rainbow Valley Park is 4/1/2 inches. The scale is 1/2 inch: 3 miles. What is the
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so, we can multiply both sides by 9

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Which theorem is the following?
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3 years ago
Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
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