-5*3+2-7+3*6= -15+3-7+18= -1
Answer:
1/21.
Step-by-step explanation:
There are 9 digits and the total number of permutations of 3 from 9 is 9P3
= 9!/6! = 504.
There are 4 even digits so the number of permutations of 3 from these 4 is 4! (4-3)! = 4*3*2 = 24.
So the required probability = 24/504
= 1/21.
I believe the answer is A
Answer:
I18 - xI such that x < 18.
ok, first let's what happens if x = 18:
I18 - xI = I18 - 18I = 0
So, at the moment we have the condition:
I18 - xI > 0.
now, if x is a really large negative number, suppose, x = -100
I18 + 100I = I118I = 118
So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:
I18 - xI > 0.
This means that the domain is:
D = (-∞, 18)
and the range is:
R = (0, ∞)
I think in commutative properties of multiplication:
70 x 6000 = 70 x 6000
420,000 = 420,000
I don't know associative properties, only commutative properties. Sorry :(
