Question

a random sample of 500500500 residents of a town included 173173173 residents who primarily spoke a language other than english at home, with a margin of error of 252525 residents and a confidence level of 98\��, percent. if the town has 25{,}00025,00025, comma, 000 residents, how many residents primarily speak a language other than english at home, with the 98\��, percent confidence level?

Answer 1

If sample size is 500,number of residents who primarily spoke a language other than english at home is 173, margin of error is 25 and the confidence level is 98%,then the number of residents from 25000 who primarily spoke a language other than english at home will be 9900.

Given that sample size is 500,number of residents who primarily spoke a language other than english at home is 173, margin of error is 25 and the confidence level is 98%.

We are required to find the number of residents from 25000 who primarily spoke a language other than english at home.

Percentage of residents who spoke language other than english at home=173/500 *100=34.6%

Percentage of margin of error=25/500*100=5%

Number of residents among 25000=25000*34.6%=8650

Margin of error for 25000=25000*5%=1250

Total number of residents who spoke other than english at home=8650+1250=9900 residents

Hence If sample size is 500,number of residents who primarily spoke a language other than english at home is 173, margin of error is 25 and the confidence level is 98%,then the number of residents from 25000 who primarily spoke a language other than english at home will be 9900.

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