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Vikki [24]
1 year ago
9

Please help will mark brainliest

Mathematics
1 answer:
tankabanditka [31]1 year ago
7 0

answer should be A since its by months C would be Y and M be X since its charging per movire

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You are holding a glass of orange juice with ice cubes floating on it.
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You are holding a heterogeneous mixture but once the ice cubes melt the mixture will become homogeneous. A heterogeneous mixture is when you can see and separate the different parts of the item you have. A homogeneous solution is when you can't separate the item you have by physical means<span />
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Find the value of x. <br> (6x+8) <br> (7x-7)
dimaraw [331]

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3 years ago
Akira is a salon owner. Yesterday, she did 2 haircuts and colored the hair of 1 client, charging a total of $194. Today, she did
joja [24]

Answer:

\boxed {\boxed {\sf Haircut: \$47 \ and \  Color: \$ 100}}

Step-by-step explanation:

Let's set up a system of equations. (1 equation for yesterday and 1 for today).

  • Let h = haircut and c= color

2h+1c= 194  (Yesterday: 2 haircuts and 1 color for $194).

2h+4c= 494 (Today: 2 haircuts and 4 colors for $494).

Notice that both equations have a 2h. If we subtract the two equations, the 2h will cancel and leave us with one variable, c.

\ \ (2h+1c=194) \\-  (2h+4c=494)

\ \ 1c=194 \\- (4c=494)

-3c= -300

Since we are solving for c, we must isolate the variable. It is being multiplied by -3. The inverse of multiplication is division. Divide both sides by -3.

-3c/-3=-300/-3 \\c= -300/-3 \\c=100

Now we have to solve for h. Plug 100 in for c in the first equation.

2h+1(100)= 194 \\2h+100=194

100 is being added, so we must subtract 100 from both sides.

2h+100=194-100 \\2h=94

h is being multiplied by 2, so we divide both sides by 2.

2h/2=94 \\h=47

A haircut costs $47 and a color costs $100.

6 0
3 years ago
Plz help I need help
VMariaS [17]

Answer:

the answer is C) 7 and -7

Step-by-step explanation:

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1. Find the number of real number solutions for the equation.
exis [7]

Answer:

b. 2

Step-by-step explanation:

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3 years ago
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