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2 years ago

Plz help I need help

Mathematics

2 answers:

VMariaS [17]2 years ago

7 0

Answer:

the answer is C) 7 and -7

Step-by-step explanation:

valina [46]2 years ago

3 0

Answer:

C) 7 and -7

Step-by-step explanation:

<em>Please mark as brainliest!</em>

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Sever21 [200]

Answer:

Hey there!

The range is the possible y values, so the range of this graph would be all real numbers less than or equal to -6.

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Circle X with a radius of 6 units and circle Y with a radius

asambeis [7]

Answer:

Option C.

Step-by-step explanation:

It is given that radius of circle X is 6 units and radius of circle Y is 2 units.

Here, circle Y is smaller and circle X is larger.

$\text{Scale factor}=\dfrac{\text{Radius of circle X}}{\text{Radius of circle Y}}$

$\text{Scale factor}=\dfrac{6}{2}$

$\text{Scale factor}=3$

If we translate the circles so they share a common center point, and after that we dilate circle Y by a scale factor of 3, then we get circle which is equal to circle X.

We know that, after dilation the figure and its image are similar.

Hence, we can say that both circles are similar.

Therefore, the correct option is C.

8 0

3 years ago

X^-2+4x^-1+3=0 solve by making appropriate substitution

Alex

ANSWER

$x = - 1 \: or \: x = - \frac{1}{ 3}$

EXPLANATION

The given equation is:

${x}^{ - 2} + 4 {x}^{ - 1} + 3 = 0$

Recall that:

${a}^{ - m} = \frac{1}{ {a}^{m} }$

$\frac{1}{ {x}^{2} } + \frac{4}{x} + 3 = 0$

${( \frac{1}{x} )}^{2} + 4( \frac{1}{x} ) + 3 = 0$

Let

$u = \frac{1}{x}$

Our equation then becomes:

${u}^{2} + 4u + 3 = 0$

The factors of 3 that add up to 4 are:

${u}^{2} + 3u + u + 3$

$u(u + 3) + 1(u + 3) = 0$

$(u + 1)(u + 3) = 0$

$u + 1 = 0 \: or \: u + 3 = 0$

$u = - 1 \: or \: u = - 3$

This implies that:

$\frac{1}{x} = - 1 \: or \: \frac{1}{x} = - 3$

$x = - 1 \: or \: x = - \frac{1}{ 3}$

7 0

3 years ago