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sergejj [24]
11 months ago
14

If line KM bisects angle JKL, angle JKL = 92 degrees, and angle MKL = (5x+1) degrees, find the value of

Mathematics
1 answer:
kherson [118]11 months ago
6 0

The value of the variable x is found to be x = 9.

<h3>What is termed as angle bisector?</h3>
  • In geometry, an angle bisector is a line that divides an angle into two equal angles.
  • A bisector is something that divides a shape or thing into two equal portions.
  • An angle bisector is a ray that divides an angle into two equal components of the same measurement.

A bisected angle divides the two sides in equals.

JKM = LKM

As, both are equal.

Then, each of these angles are 1/2 the angle JKL.

1/2 JKL = MKL

1/2 ×( 92) = 5x + 1

Further simplifying;

46 = 5x+1

Subtract 1 from each side

46-1 = 5x

45 = 5x

Divide each side by 5

45/5 = 5x/5

x = 9

Thus, the value of the unknown variable is found to be x = 9 units.

To know more about the angle bisector, here

brainly.com/question/14399747

#SPJ9

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sweet-ann [11.9K]

12-pack for 1.69 is a better buy

<em><u>Solution:</u></em>

Given that, Mike bought a 12-pack for 1.69 and Mary bought a 24-pack for 3.18

We have to find which is the better buy

First we have to find the unit rate

Unit rate is cost of 1 pack

<em><u>Mike bought a 12-pack for 1.69</u></em>

Therefore,

Cost of 12 pack = 1.69

Cost of 1 pack is found by dividing 1.69 by 12

cost\ of\ 1\ pack = \frac{1.69}{12} = 0.14083

Thus unit rate of Mike is 0.14083 dollar per pack

<em><u>Mary bought a 24-pack for 3.18</u></em>

Cost of 24 pack = 3.18

Cost of 1 pack is found by dividing 3.18 by 24

cost\ of\ 1\ pack = \frac{3.18}{24} = 0.1325

Thus unit rate of Mary is 0.1325 dollars

<em><u>On comparing both the unit rate</u></em>

0.14083>0.1325

Thus unit rate of Mike is larger

Thus, 12-pack for 1.69 is a better buy

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3 years ago
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Olin [163]

Answer:

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Step-by-step explanation:

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y is 128 because both those angles are equal

the other 2 angles are also equal to each other.

360 - 128-128= 104

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Step-by-step explanation:

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