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Orlov [11]
1 year ago
11

2x - 12 = 2(x-10)-87

Mathematics
1 answer:
bogdanovich [222]1 year ago
4 0

The equation 2x - 12 = 2(x-10)-87 has no solutions.

Given: To find the value of x: 2x - 12 = 2(x - 10) - 87

What are algebraic expressions?

Algebraic expressions are sequences or combinations of characters containing letters, numbers, symbols, operators, and variables which are used to derive a certain relation among all of them.  

What is an algebraic equation?

When an algebraic expression has a value it becomes an algebraic equation. The algebraic equation helps to make a relation between different variables for a problem.

Let's solve the question.

2x - 12 = 2(x - 10) - 87

Adding 12 on both sides:

2x - 12 + 12 = 2(x-10) - 87 + 12

=> 2x = 2(x -10) - 75

=> 2x = 2x - 20 - 75

=> 2x = 2x - 95

Adding -2x on both sides:

2x - 2x = 2x - 95 - 2x

0 = -95

This is contradictory.

The equation is independent of x, and 0 = -95 is false. Therefore, the equation has no solutions.

Hence the equation 2x - 12 = 2(x-10)-87 has no solutions.

Know more about "algebraic expressions" here: brainly.com/question/953809

#SPJ9

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the
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Answer:

\left(100\pi - 150\sqrt{3}\right) square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 10 inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment \sf CH be a height on side \sf AB. Since this triangle is equilateral, the size of each internal angle will be \sf 60^\circ. The length of segment

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The area (in square inches) of this equilateral triangle will be:

\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}.

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}.

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is 10 inches, the radius of this circle will also be 10 inches.

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\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi.

The area (in square inches) of the circle that the hexagon did not cover would be:

\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}.

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