Sum of the arithmetic sequence-Find each sum- 2 + 5 + 8 + ... +41
2 answers:
Answer: S=301
Step-by-step explanation:
2 + 5 + 8 + ... +41
The difference of an arithmetic progression:
Any (nth) term of the progression can be calculated using the formula for the total term:
Divide both parts of the equation by 3:
The sum of all the members of an arithmetic progression is equal to half the product of the sum of its outermost members by the number of all its members. where S is the sum of all the members, a₁ is the first member of the progression, an is the last member, and n is the number of members in the given progression:
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Answer:
(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}
(b) The probability that Roberto and John attend the conference is 0.10.
(c) The probability that Clarice attends the conference is 0.40.
(d) The probability that John stays home is 0.60.
Step-by-step explanation:
It is provided that :
Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.
The company selects two employees randomly to attend a statistics conference.
(a)
There are 5 employees from which the company has to select two employees to send to the conference.
So the total number of ways to select two employees is:
The 10 possible samples are:
MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC
(b)
The probability of the event <em>E</em> is:
Here,
n (E) = favorable outcomes
N = Total number of outcomes.
The variable representing the selection of Roberto and John is, <em>RJ</em>.
The favorable number of outcomes to select Roberto and John is, 1.
The total number of outcomes to select 2 employees is 10.
Compute the probability that Roberto and John attend the conference as follows:
Thus, the probability that Roberto and John attend the conference is 0.10.
(c)
The favorable outcomes of the event where Clarice attends the conference are:
n (C) = {MC, RC, JC and DC} = 4
Compute the probability that Clarice attends the conference as follows:
Thus, the probability that Clarice attends the conference is 0.40.
(d)
The favorable outcomes of the event where John does not attends the conference are:
n (J') = MR, MD, MC, RD, RC, DC
Compute the probability that John stays home as follows:
Thus, the probability that John stays home is 0.60.