Answer:
I've been trying to figure this out with out a chart and i keep confusing myself
Step-by-step explanation:
nothing
Answer:
30
Step-by-step explanation:
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Answer:
Step-by-step explanation:
y=x^2-x+1
We want to solve for x.
I'm going to use completing the square.
Subtract 1 on both sides:
y-1=x^2-x
Add (-1/2)^2 on both sides:
y-1+(-1/2)^2=x^2-x+(-1/2)^2
This allows me to write the right hand side as a square.
y-1+1/4=(x-1/2)^2
y-3/4=(x-1/2)^2
Now remember we are solving for x so now we square root both sides:
The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.
This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.
That is we want:
Add 1/2 on both sides:
The last step is to switch x and y:
Answer:
f(x) = 3x + 2
Step-by-step explanation:
That's easy to find out. You have your input number, which is your x value, and you have your output number which is your y value (or f(x)).
All you have to do is see if each of the proposed answer works for ALL entries in the data set.
f(x) = 3x + 2
for x = 3 ===> 11 = 3 (3) + 2 = 11 YES
for x = 5 ===> 17 = 3 (5) + 2 = 17 YES
for x = 7 ===> 23 = 3 (7) + 2 = 23 YES
for x = 9 ===> 29 = 3 (9) + 2 = 29 YES
f(x) = 2x + 5
for x = 3 ===> 11 = 2 (3) + 5 = 11 YES
for x = 5 ===> 17 = 2 (5) + 5 = 15 NO - we stop here for this function
f(x) = x + 7
for x = 3 ===> 11 = (3) + 7 = 10 NO - we stop here for this function
f(x) = 3x + 1
for x = 3 ===> 11 = 3 (3) + 1 = 10 NO - we stop here for this function
The line passes through two points that have the same x-coordinate.
It is a vertical line. To find the slope of a line, use any two points. Subtract the y-coordinates. Subtract the x-coordinates in the same order. Then divide the difference of the y-coordinates by the difference of the x-coordinates. Since in this case, the x-coordinates are both -6, the difference between the x-coordinates is zero. Division by zero is not defined, so the slope of this line is undefined. You can't write its equation in point-slope form, because there is no slope for this line.
