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3 years ago

Find the missing length indicated. х 12 9 X = units

Mathematics

1 answer:

madam [21]3 years ago

8 0

Answer:

Step-by-step explanation:

9/12=12/x

x=16

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What is 2 6/7 times 1 1/3

worty [1.4K]

The answer is 3.80952380952

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3 years ago

Read 2 more answers

Which statements about the system are true? Select two options.

butalik [34]

Answer:

no solution

Step-by-step explanation:

y = (1/3)x - 4

3y - x = -7

put the first equation into the second

3(1/3)x - (3)4 - x = -7

x - 12 - x = -7

-12 = -7 can never be true so this is no solution

6 0

2 years ago

How do you do solve this question?

vampirchik [111]

In 14 minutes, Dan has already traveled 840 miles

14 • 60 = 840

Since Jake bikes 210 per minute, you would need to divide the total number of miles that Dan has traveled in 14 minutes (840 miles) by the amount of miles Jake can travel in one minute (210).

840 ÷ 210 = 4 minutes

Answer: 4 minutes

7 0

4 years ago

If a train was traveling at 80 mph to the next station and it arrived 6 hours later, how far the train travel to get to the stat

Alex

460 miles away. just take how many miles an hour the train is going and multiply how many hours it took to get there, which would be 460

6 0

3 years ago

A company manufactures tires at a cost of $40 each. The following are probabilities of defective tires in a given production run

asambeis [7]

Answer:

The expected cost of the company for a 3000 tires batch is $120255

Step-by-step explanation:

Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.

Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are $A_1,\dots, A_n$ events that partition the whole sample space, and we have a random variable X over the sample space, then

$E(X) = p(A_1)E(X|A_1) + \dots + p(A_n)E(X|A_n)$ .

So, in this case, we have the following

$E(X) = P(p=0\%)E(X|p=0\%)+P(p=1\%)E(X|p=1\%)+P(p=2\%)E(X|p=2\%)+P(p=3\%)E(X|p=3\%) = 0.1\cdot 3000\cdot 0 + 0.3\cdot 3000\cdot 0.01+ 0.4\cdot 3000\cdot 0.02+ 0.2\cdot 3000\cdot 0.03 = 51$ .

Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.

Finally, note that the cost of the batch would be 40Y+45X. Then

$E(40Y+45X) = 40E(Y)+45E(X) = 40\cdot 2949+45\cdot 51=120255$

3 0

3 years ago