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Free_Kalibri [48]
1 year ago
7

Sara made an error in solve the one-step equation below.5x + 9 = 29-9 -9- 4x = 29/4. /4x = -7.25What is the error that Sara made

?What should Sara had done to solve the one-step equation above insteadof what she did?What is the answer that Sara should have found for the above one-step equation?*
Mathematics
1 answer:
MAXImum [283]1 year ago
8 0
5x+9=29

To solve this one-step equation you:

1. Substract 9 in both sides of the equation:

In this step is the mistake as Sara gets as result -4x=29 and the corret result of substract 9 in both sides of the equation is 5x=20.

2. Divide both sides of the equation into 5:

Then, the answer that Sara should found for the equation is x=4

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Express the equation in rectangular form<br> a) r = 2sin(2Θ)<br> b) r = 4cos(3Θ)
Dafna11 [192]

Answer:

a.  sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b.  (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know  sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r  and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2)  and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that  sin theta = y/r  and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know  r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

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If f(x)=3x, g(x)=x+4, and h(x)=x2-1, find the value of f[g(1)]
Strike441 [17]

Answer:

15.

Step-by-step explanation:

The given functions are

f(x)=3x

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h(x)=x^2-1

We need to find the value of f[g(1)].

f[g(1)]=f[(1)+4]          [\because f[g(1)]=f[(1)+4]]

f[g(1)]=f[5]

f[g(1)]=3(5)           [\because f(x)=3x]

f[g(1)]=15    

Therefore, the value of f[g(1)] is 15.

4 0
3 years ago
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