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Kamila [148]
2 years ago
8

Amy has a box containing 6 white, 4 red, and 8 black marbles. She picks a marble randomly. It is red. The second time, she picks

a white marble. In the third attempt, Amy picks a white marble again. Amy has not replaced the marbles she picked. The probability that the fourth marble Amy picks is black is . If Amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is____.
Mathematics
1 answer:
Sladkaya [172]2 years ago
6 0
After the 3rd pick we have: 4 white, 3 red and 8 black marbles.
The probability that the 4th marble is black is:
P ( Black ) = 8 / 15 = 0.5333
After the 4th pick we have: 4 white, 3 red and 7 black marbles.
P ( Red or Black ) = 10 / 14 = 5 / 7 = 0.7143
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Answer:

  1. 96
  2. 6.9
  3. 25%
  4. 8%
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  6. 33.8

Step-by-step explanation:

Here is the complete question: Find each number. Round to the nearest tenth if necessary.

  1. 80% of 120.
  2. 115% of 6
  3. What percent of 128 is 32?
  4. 3 is what percent of 36?
  5. 23.7 is 30% of what number?
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1) 80% of 120

= \frac{80}{100} \times 120= 8\times 12

= 96

∴ 80% of 120= 96

2) 115\%\ of\ 6

=\frac{115}{100}\times 6= 1.15\times 6

∴ 115\%\ of\ 6 = 6.9

3) What percent of 128 is 32?

= \frac{32}{128} \times 100

= 25\%

4) 3 is what percent of 36?

= \frac{3}{36} \times 100

= 8\%

5) 23.7 is 30% of what number?

Let the number be "x".

⇒ \frac{30}{100} \times x= 23.7

Cross multiplying

⇒ x= \frac{23.7\times 100}{30}

∴ x= 79.

6) 71/2% of what is 12?

Lets assume the required number be "x".

⇒ \frac{71}{2} \times 100\times x= 12

cross multiplying both side.

⇒x= 33.8

∴ 71/2% of 33.8 is 12

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