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1 year ago

15. Evaluate the expression 13 ÷ (2.5-1-3).33.

Mathematics

1 answer:

OlgaM077 [116]1 year ago

3 0

Evaluation of the expression using order of operation gives 26/11.

How to evaluate the expression

Given 13 ÷(2.5-1-3).33 = 13 ÷ 33( 2 x 5 - 1 - 3)

To evaluate this expression we need to apply the order of operation rule, BODMAS or PEMDAS.

13 ÷(2.5-1-3).33 = 13 ÷ 33( 2 x 5 - 1 - 3) Evaluate multiplication

= 13 ÷ 33(10 - 1 - 3) Evaluate what is in the bracket

= 13 ÷ 33(6) Evaluate division

= 13/33 x 6

= 78/ 33 = 26/11

Therefore, evaluating the expression gives 26/11.

Learn more about the order of operation on:

brainly.com/question/28360611

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b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

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