Problem 1)
Answer: 20 feet
We have two base angles that are congruent, so that implies we have an isosceles triangle. With isosceles triangles there are exactly two congruent sides. So PD = PC = 20
---------------------------------------------------------------------
Problem 2)
Answer: 168 feet
Each leg of each triangle is equal to 42 ft. The reason why is because we have congruent triangles so all of the corresponding parts are congruent. For any given right triangle, the two legs are equal in length.
We have 4 sections of 42 ft, so 4*42 = 168 ft in total
---------------------------------------------------------------------
Problem 3)
Answer: Yes it is long enough
Let a, b, and c be the three sides
a = 5
b = 4
c = 2
Note these three properties:
Property 1: a+b = 5+4 = 9 is larger than c = 2
Property 2: b+c = 4+2 = 6 is larger than a = 5
Property 3: a+c = 5+2 = 7 is larger than b = 4
Since all three properties hold true, this means that we can construct a triangle with these side lengths. Put another way, take any two sides and add them up. The result being larger than the third side allows a triangle to be formed. This is the triangle inequality theorem.
---------------------------------------------------------------------
Problem 4)
Answer: 55 degrees
x = base angle
we have two base angles plus the vertex angle of 70 degrees
The three angles (x, x, 70) must add to 180
x+x+70 = 180
2x+70 = 180
2x+70-70 = 180-70
2x = 110
2x/2 = 110/2
x = 55
Therefore, each base angle is 55 degrees
If we call y the height of the plane, we know when the time (x) is 0, the height is 30000. So let's write that in:
y = 30000 + (0)
Then, for every increase of a minute (x increases by 1), the height reduces by 2000. This can be written as:
y = 30000 - 2000x
Using what we know about y = mx+c equations, the slope of the line is -2000, and the y-intercept is (0, 30000).
Sqrt(220)= sqrt(2•2•5•11)=2 sqrt (5•11)=
2 sqrt(55)
So no the radical was not in it’s simplest form
The answer to this equation is: 7q +12
Answer:
A
Step-by-step explanation: