Question

Using a table of values, determine the solution to the equation below to the nearest fourth of a unit.2x - 4 = 3-x + 1A. x=2.5B. x=1C. x=2D. x= 3.25

Answer 1

The equation is:

$2x-4=3^{-x}+1$

Now we can evaluate the posible values of x so:

for x=2.5

$2(2.5)-4=3^{-2.5}+1$

so now we operate:

$\begin{gathered} 5-4=0.06+1 \\ 1=0.06+1 \\ 0\approx0.06 \end{gathered}$

For x=1

$2(1)-4=3^{-1}+1$

Now we operate:

$\begin{gathered} 2-4=0.33+1 \\ -2\ne1.33 \end{gathered}$

for x=2

$\begin{gathered} 2(2)-4=3^{-2}+1 \\ 4-4=0.11+1 \\ 0\ne1.11 \end{gathered}$

and for x=3.25

$\begin{gathered} 2(3.25)-4=3^{-3.25}+1 \\ 6.5-4=0.02+1 \\ 2.5\ne1.02 \end{gathered}$

So the clousest one is the option A