Question

In triangle PQR, Q=72 degrees, R=32 degrees and PR=12. find PQ

Answer 1

Answer:

6.69 to the nearest hundredth

Step-by-step explanation:

Use the law of sines

Let x = PQ

$\frac{sin 72}{12} = \frac{sin 32}{x}$

x sin 72 = 12 sin 32

$x = \frac{12 sin 32}{sin 72}$

x = 6.69 to the nearest hundredth