How do you find the perimeter on a coordinate plane
1 answer:
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The answer:
the main rule of transformation are as follow
Reflection:a reflection in the line y = x changes the point (x; y) to (y; x)
the transformation T(a, b), changes changes the point (x; y) to (x+a ; y+ b)
the construction of the image is as follow:
as for T(3, 7), the image is T"(8, 1)
so with the reflection in the line y = x, T(3, 7) becomes T' (7, 3), and with the transformation T(1, –2), the point T' (7, 3) becomes (7+1, 3 -2) =T"(8, 1)
with the reflection in the line y = x, U(6, –6) becomes U'(-6, 6), and with the transformation T(1, –2), the point U'(-6, 6) becomes (-6 +1, 6-2)=U"(–5, 4)
with the reflection in the line y = x, V(5, –9) becomes V'(-9, 5), and with the transformation T(1, –2), the point V'(-9, 5) becomes (-9 +1, 5-2)=U"(–8, 3)
so the final answer is
<span>r y = x and then T(1, –2)</span>
the main rule of transformation are as follow
Reflection:a reflection in the line y = x changes the point (x; y) to (y; x)
the transformation T(a, b), changes changes the point (x; y) to (x+a ; y+ b)
the construction of the image is as follow:
as for T(3, 7), the image is T"(8, 1)
so with the reflection in the line y = x, T(3, 7) becomes T' (7, 3), and with the transformation T(1, –2), the point T' (7, 3) becomes (7+1, 3 -2) =T"(8, 1)
with the reflection in the line y = x, U(6, –6) becomes U'(-6, 6), and with the transformation T(1, –2), the point U'(-6, 6) becomes (-6 +1, 6-2)=U"(–5, 4)
with the reflection in the line y = x, V(5, –9) becomes V'(-9, 5), and with the transformation T(1, –2), the point V'(-9, 5) becomes (-9 +1, 5-2)=U"(–8, 3)
so the final answer is
<span>r y = x and then T(1, –2)</span>
Given 
, 
is in Quadrant IV, 
, and 
is in Quadrant III, find 
We can use the angle subtraction formula of sine to answer this question.
We already know that.
We can use the Pythagorean identity
to find 
.
Since is in Quadrant IV, and sine is represented as y value on the unit circle, we must assume the negative value 
.
As similar process is then done with.
And since is in Quadrant III, and cosine in represented as x value on the unit cercle, we must assume the negative value 
.
Now we can fill in our angle subtraction formula!
We can use the angle subtraction formula of sine to answer this question.
We already know that
We can use the Pythagorean identity
Since
As similar process is then done with
And since
Now we can fill in our angle subtraction formula!