Answer:
Let E denote the event of choosing a jury with 10 men and 2 women.
The sample space for selecting 12 members from the pool contains 55C12 elements.
The number of ways of selecting 10 men and 2 women is 26C10 29C2.
The probability of event E =
The probability of selecting a jury with 10 men and 2 women is 0.005 (0.5%).
Step-by-step explanation:
see the image :
Answer:
48 because i720 divided into 15 groups calculate to 48
Let P(a, b) be a point on the coordinate plane. Then the following hold:
i) If a>0, b>0 then P is in the I.Quadrant.
ii) If a<0, b>0 then P is in the II.Quadrant.
iii) If a<0, b<0 then P is in the III.Quadrant.
iv) If a>0, b<0 then P is in the IV.Quadrant.
v) If a=0 and b is positive or negative, then P is on the y-axis.
vi) If b=0 and a is positive or negative, then P is on the x-axis.
Since we have: a=0, and 19 positive, then this point is on the y-axis.
Answer: y-axis
Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .
