The required probability for P(x<92) is 0.15866.
Given that,
Sample score = X = 92
Mean = μ = 98
Standard deviation = σ = 6
p(x ≤ 92 ) is to be determined
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
z = (X - μ) / σ
z = (92 - 98) / 6
z = - 1
Now
Probability,
p(x < 92) = P(z = -1)
p(x < 92) = 0.15866 (from z score table)
Thus, The required probability for P(x<92) is 0.15866.
Learn more about probability here:
brainly.com/question/14290572
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