Answer:
80 maybe no ummm udk sorry I might
Step-by-step explanation:
I got you I think
We will get the number of possible selections, and then subtract the number less than 25 cents.
We can choose the number of dimes 5 ways 0,1,2,3 or 4.
We can choose the number of nickels 4 ways 0,1,2 or 3.
We can choose the number of quarters 3 ways 0,1, or 2.
That's 5*4*3 = 60 selections
Now we must subtract from the 60 the number of selections of coins that are less than 25 cents. These will involve only dimes and nickels.
To get a selection of coin worth less than 25 cents:
If we use no dimes, we can use 0,1,2 on all 3 nickels.
That's 4 selections less than 25 cents. (that includes the choice of No coins at all in the 60, which we must subtract).
If we use exactly 1 dime , we can use 0,1,2, or all 3 nickels.
That's the 3 combinations less than 25 cents.
And there is 1 other selection less than 25 cents, 2 dimes and no nickels.
So that's 4+3+1 = 8 selections which we must subtract from the 60.
Answer 60-8 = 52 selections of coins worth 25 cents or more.
For the first day we have the following function:
f (n) = (0.3 * 10) n + 8
For the second day we have the following function:
f (n) = (0.4 * 10) n + 5
You spent the same amount of money as the day before:
(0.3 * 10) n + 8 = (0.4 * 10) n + 5
3n + 8 = 4n + 5
n = 8-5
n = 3 items
We evaluate each function for n = 3
f (3) = (0.3 * 10) * 3 + 8 = 17 $
f (3) = (0.4 * 10) * 3 + 5 = 17 $
The total amount of money is:
17 + 17 = 34 $
Answer:
you purchase 6 items
you spend at the craft store during the sale $ 34
It looks like the differential equation is
Multiply both sides by 1/(<em>x</em> + 1) :
The left side is now a derivative of a product,
Integrate both sides with respect to <em>x</em> :
Solve for <em>y</em> :
