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lianna [129]
1 year ago
14

Suppose your team is finishing a project and the supervisor stresses ensuring the material cannot be erased. To what memory leve

l is
your supervisor referring?
Computers and Technology
1 answer:
Sedaia [141]1 year ago
6 0

Read-Only

Explanation:

As opposed to random-access storage (temporary storage), read-only storage will store data in a way that is very hard to accidentally erase, and will only be erased with an intentional effort to do so.

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Advantages and disadvantages of java
solong [7]

Answer:

1. Java is Simple · 2. Java is an Object-Oriented Programming language · 3. Java is a secure language · 4. Java is cheap and

Explanation:

5 0
3 years ago
It is good practice, however, for policy _________________________ to solicit input both from technically adept information secu
s2008m [1.1K]

Answer:

It is good practice, however, for policy <u>Administrator </u>to solicit input both from technically adept information security experts and from business-focused managers in each community of interest when making revisions to security policies.

<u>Explanation</u>

Administrator is the person who has access to each part of the computer. Ha has rights to revise, add or edit application. The administrator is authorized to make and implement policies that are for the interest of the community.

7 0
3 years ago
A large population of ALOHA users manages to generate 50 requests/sec, including both originals and retransmissions. Time is slo
krok68 [10]

Answer:

The answer is below

Explanation:

Given that:

Frame transmission time (X) = 40 ms

Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request

a) Probability that there is success on the first attempt = e^{-G}G^k but k = 0, therefore Probability that there is success on the first attempt = e^{-G}=e^{-2}=0.135

b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)

P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = [1-e^{-G}]^k=[1-0.135]^k=0.865^k

P(success in k+1 attempt) = e^{-G}=e^{-2}=0.135

Probability of exactly k collisions and then a success = 0.865^k0.135

c) Expected number of transmission attempts needed = probability of success in k transmission = e^{G}=e^{2}=7.389

6 0
3 years ago
You work in an office that uses Linux and Windows servers. The network uses the IP protocol. You are sitting at a Windows workst
Aleksandr-060686 [28]

Answer:

PING

Explanation:

To check if there's still connectivity between the computer and server, I would use the ping command.

The ping command is primarily a TCP/IP command. What this command does is to troubleshoot shoot. It troubleshoots connection and reachability. This command also does the work of testing the name of the computer and also its IP address.

4 0
3 years ago
This is your code.
lubasha [3.4K]

Answer:

35

Explanation:

We will be going inside B array, because he was in second place in array E,and will be the first element of array B, so it's 35

E can be understanded as:

E=[[21, 'dog', 'red'],[35, 'cat', 'blue'],[12, 'fish', 'green']], so, you can see array E as array of arrays or so-called two-dimensional array

6 0
2 years ago
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