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Natali5045456 [20]
1 year ago
6

For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x < -3h(x) = { 5, for - 35x<5for

x>5x+1,h(-6)=
Mathematics
1 answer:
sleet_krkn [62]1 year ago
5 0

Given the piecewise function h(x):

h(x)=\begin{cases}-5x-13,x

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

h(x)=-5x-13

Replace the expression with x=-6 and calculate the corresponding value of x:

\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

h(x)=5

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that:

h(0)=5

3) For h(5), you have to determine the value of h(x) for x=5, for values of x greater than or equal to 5, h(x) has the following shape:

h(x)=x+1

Replace the expression with x=5 and calculate the corresponding value of h(x):

\begin{gathered} h(5)=5+1 \\ h(5)=6 \end{gathered}

4) For h(9), you have to determine the value of h(x) when x=9, 9 is greater than 5, for this value of x, the function has the following shape:

h(x)=x+1

Replace the expression with x=9, and calculate the corresponding value of h(x):

\begin{gathered} h(9)=9+1 \\ h(9)=10 \end{gathered}

So, to sum up:

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Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).
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Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

Step-by-step explanation:

Given the points

  • (-4,1)
  • (4,3)

Finding the slope between the points (-4,1) and (4,3)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)

m=\frac{3-1}{4-\left(-4\right)}

Refine

m=\frac{1}{4}

Point slope form:

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

in our case,

  • m = 1/4
  • (x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

y-y_1=m\left(x-x_1\right)

y-1=\frac{1}{4}\left(x-\left(-4\right)\right)

y-1=\frac{1}{4}\left(x+4\right)

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

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3a.) Today, everything at a store is on sale. The store offers a 20% discount. 1 poin
Novay_Z [31]

Answer:

14.40

Step-by-step explanation:

100%-> 18

100-20=80

80%-> 14.40

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