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1 year ago

PLEASE ANSWER CLEARLY WITH THE EQUATION

1 answer:

5 0

After solving the provided question, Aisha spent 7.9 hours and 9.9 hours, respectively, working last week as a babysitter and a landscaper.

<h3>Which is an equation?</h3>

A mathematical statement that has at least two terms, both of which contain variables or equal integers, is defined as an equation.

Aisha is reportedly working two summer jobs, earning $7 an hour for babysitting and $8 an hour for gardening.

Let's say you were to watch the children for x hours.

And y would be the amount of hours spent on landscaping.

Last week, Aisha spent two more hours babysitting than a landscaper, earning a total of $134.

$y = x + 2\\7x + 8y = 134\\Substitute the value of y = x + 2 in the equation,\\7x + 8(x + 2) = 134\\7x + 8x + 16 = 134\\15x = 134 - 16\\15x = 118\\x = 118/15\\x = 7.9\\Substitute the value of x = 7.9 in the equation y = x + 2 ,\\y = 7.9 + 2\\y = 9.9\\$

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Please help fast !!!!!!!!!

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Answer:

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3 years ago

The cost of fencing a Square Garden is 400 at the rate of 1 per metre find its length

grin007 [14]

Here Is The Answer:

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Hope It Helps You!!!

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3 years ago

What is the slope-intercept form of the function that contains the point (–1, 5) and has a slope of –4?

katovenus [111]

If it has a slope of -4, you need to find b.

So you want to plug in your coordinate values for x and y to solve.

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1=b

So your equation would be:

y=-4x+1

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4 years ago

A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re

fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer $E_0$ and the current temperature $E(t)$ where $t$ is the elapsed time in minutes. The outside temperature is 20 F.

Newton's Law of Cooling:

$E(t) - 20 = (E_0 - 20) e^{- k t}$

We're given $E(1)=70 \textrm{ and } E(5)=45$

$70-20 = (E_0 - 20) e^{-k}$

$45-20 =(E_0 - 20) e^{-5k}$

Dividing,

$\dfrac{50}{25}=e^{4k}$

$k = \dfrac 1 4 \ln 2$

Now,

$E(t) - 20 = (E_0 - 20) e^{- k t}$

$E_0 = 20 + (E(t) - 20)e^{k t}$

$E_0 = 20 + (E(1) - 20)e^{k}$

$E_0 = 20 + (70 - 20)e^{\ln 2/4}$

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4 years ago

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horsena [70]

Answer:

1,5,6

Step-by-step explanation:

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3 years ago

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