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Stels [109]
3 years ago
11

18 tens 20 ones equal what hundreds

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0

Answer:

The answer is 2 hundreds.

Step-by-step explanation:

In order to determine the answer, we have to know about the notation numbers. In any number, every digit has a notation, depending on its position in the number.

I have attached an image that shows some notation numbers.

According to the image, we can see that:

"tens" means 10

"ones" means 1

So if a number is together to this notation, we can multiply both of them:

18 tens= 18 x 10= 180

20 ones= 20 x 1= 20

Adding both numbers:

180+20=200

Then, we need to know about "hundreds":

"hundreds" means 100

So, if we have 200, it is the same that 2 hundreds.

Finally the answer is 2 hundreds.

pickupchik [31]3 years ago
3 0
$20 in ones and $180 in tens 
there is a total of $200 dollars
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Linda's start up cost for her online jewelery store was $250, as she has to pay an additional $60per month to keep it running. W
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Total Cost = 250 + 60x is the equation that models the given situation

<em><u>Solution:</u></em>

Given that, Linda's start up cost for her online jewelery store was $250

She has to pay an additional $60 per month to keep it running

To find: Equation that models this situation

From given,

Start up cost = $ 250

Let "x" be the number of months she keeps the store running

Additional pay per month = $ 60

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Total Cost = Startup cost + (Additional pay per month)(number of months)

Total\ Cost = 250 + 60x

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3 years ago
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Step-by-step explanation:

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3 years ago
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
3 years ago
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