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11 months ago

2) (3 pt) Write the function from the table and graph.хf(x)-10004122130.52) f(x) =

Mathematics

1 answer:

DaniilM [7]11 months ago

4 0

(x - h)^2 = 4p(y - k)

(-1 - 3)^2 = 4p(8 - 0.5)

(-4)^2 = 4p(7.5)

16 = 30p

p = 16/30

p = 8/15

(x - 3)^2 = 16/15(y - 0.5)

15(x^2 - 6x + 9) = 16y - 8

15x^2 - 90x + 135 = 16y - 8

16y = 15x^2 - 90x + 135 + 8

y = 15/16 x^2 - 90/16 x + 143/16

f(x) = 15/16 x^2 - 90/16x + 143/16

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Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

2 years ago

50 POINTS PLZ ANSWER CORRECTLY

belka [17]

Hey there! :D

So, we want to multiply that by 2. The table represents one year at Weatherford College.

8,965*2= 17,930

I heard the question mention 'reasonable'. It also said 'meet the cost'. So I would assume that 17,930 meets most of the cost. I think that's what it wanted to have. A couple thousand dollars may be reasonable, but will it meet the cost? Probably not.

I would say "A" is the best answer.

I hope this helps!
~kaikers

7 0

2 years ago