Submit the answers to the checkpoint questions in the text box with the Lesson Review.

The graph of y = 3x - 4

zhenek [66]

Answer:

Step-by-step explanation:

5 0

3 years ago

Rebecca collected data from a random sample of 1200 homeowners in her state asking whether or not they use electric heat. Based

larisa [96]

Hi,

The answer is c. The sample is biased.

This is because the sample is taken on a single state, an Rebecca reports a statistic about the nation. Her data contains information only of her state. If she lives in a very cold state, there is probably more homeowners using electric heat than in a hot state.

6 0

3 years ago

The perimeter of a rectangle is 84 inches. The width of the rectangle is 12 inches. What is the length of the rectangle?

german

The length of the rectangle is 30

5 0

2 years ago

Somebody HELPPPPPSelect the correct answer. What is the value of this expression if a = - 7 and b = -37 a3 - b2

sergiy2304 [10]

Answer:

53

reason:

substitute a with -7 and b with -37
this makes the equation (-7)3 - (-37)2, which equals 53

7 0

3 years ago

Read 2 more answers

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

3 years ago