Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
1488 labels divided by 16 labels equals 93. So the answer is D.
The answer is A) 2n-3m-(2n+3m)
Step-by-step explanation:
First calculate the z-score.
z = (x − μ) / σ
z = (11.07 − 11.5) / 2.7
z ≈ -0.16
From a z-score table:
P(z<-0.16) = 0.4364
The proportion of babies that weigh less than 11.07 lbs is 0.4364.
Answer:
The resistance is decreasing at a rate of 0.36 ohms/minute.
Step-by-step explanation:
The mathematical form of the Ohm's law is given by :
V = IR ...(1)
Where V is voltage, I is current and R is resistance
Given,
I = 5 A
R = 6 ohms
dI/dt = 0.3 A/min
Differentiate equation (1) wrt t:

When V is constant, dV/dt = 0

So, the resistance is decreasing at a rate of 0.36 ohms/minute.