Let
rA--------> radius of the circle A
rB-------> radius of the circle B
SA------> the area of the sector for circle A
SB------> the area of the sector for circle B
we have that
rA=5/2 ft
rB=9/2 ft
rA/rB=5/9-----------> rB/rA=9/5
SA=(25/36)π ft²
we know that
if Both circle A and circle B have a central angle , the square
of the ratio of the radius of circle A to the radius of circle B is equals to
the ratio of the area of the sector for circle A to the area of the sector for
circle B
(rA/rB) ^2=SA/SB-----> SB=SA*(rB/rA) ^2----> SB=(9/5) ^2*(25/36)π--->
<span>SB----------- > (81/25)*(25/36)------ > 81/36------
> 9/4π ft²</span>
the answer is
<span>the measure of the sector for circle B is (9/4)π ft²</span>
Answer:
X=3
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Concept:
(1) Curved surface area of cylinder = Circumference of the base × Height of cylinder
(2) Area of the base = Area of circle = π × (radius)²
(3) Circumference of the base = 2×π× (radius)
Consider a right circular cylinder as given in attached figure
Its height (AB) = H
Its radius (OC) = R
Now, we shall calculate the curved surface area of the cylinder (CSA)
(CSA) = Circumference of the base × Height of cylinder
(CSA) = 2×π×R × H = 2πRH -------(i)
Again, we shall calculate the area of the top and bottom circles
Area of the top and bottom (A) = 2× Area of circle
(A) =2×[ π × (radius)²]
or, (A) = 2×π×R² = 2πR²------------(ii)
Now, we shall calculate the surface area or total surface area of the cylinder.
SA = CSA + A
SA = 2πRH + 2πR²
or, SA = 2πR² + 2πRH
This is the required equation.