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3 years ago

The following sinusoid is plotted below. Complete the following steps to model the curve using the cosine function.

Mathematics

1 answer:

solniwko [45]3 years ago

5 0

Answer:

A.) phase shift is h=6

B.) Vertical shift is 21 units down

C.) The amplitude is 5 from the midline at y= -21

D.) The period is 16 and the frequency factor is pi/8

E.) 5 cos(pi/8(x-6))-21

Step-by-step explanation:

Find your minimum and maximum values. This would help you find the amplitude and the vertical shift. To find amplitude, the formula is A= (absolute value) of the max minus the min and divide by 2. To find vertical shift, you add the max and min values and divide by 2. The period is the distance of the max and min values and then doubled. The distance was 8 units so the period was 16. To find frequency factor, just plug in your values. You know that the formula is Period= 2pi/b. So it would be 16= 2pi/b. The frequency factor should be pi/8 after you cross multiply and then divide. To write the equation, you substitute the values into the equation of acos(b(x-c))+d. Make sure to put parentheses or else the graph will look wrong.

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zysi [14]

Answer:

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Step-by-step explanation:

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2 years ago

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telo118 [61]

Answer:

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Step-by-step explanation:

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2 years ago

The sum of the first n terms of an arithmetic sequence is n/2(4n + 20).

lesantik [10]

Answer:

(a).

$S_{n} = \frac{n}{2} (4n + 20) \\ \\S _{n - 1} = \frac{(n - 1)}{2} (4n - 4 + 20) \\ \\ S _{n - 1} = \frac{(n - 1)}{2} (4n + 16) \\ \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2} \\ \\ { \boxed{S _{n - 1} = {2 {n}^{2} + 6n - 8}}} \\$

(b).

from general equation:

$S _{n - 1} = \frac{(n - 1)}{2} (4n + 16)$

first term is 4n

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2 years ago

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Ludmilka [50]

Answer:

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Step-by-step explanation:

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2 years ago

A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An

Gnom [1K]

I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
$tan A = \frac{h+70}{40} , tan B = \frac{70}{40}$

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
$tan (A-B) = \frac{tanA - tanB}{1+tan A tan B}$
Plug in what we know:
$tan(9) = \frac{ \frac{h+70}{40} - \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}$
$tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}$
$h = \frac{650 tan(9)}{4-7 tan(9)}$
$h = 35.6$

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3 years ago