susan's algebra class begins with 36 students. of 2/3 will finish the class and 3/4 of those ger a passing grade, how many stude
1 answer:
You might be interested in
Answer:
So we can find this probability:
And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:
Step-by-step explanation:
Let X the random variable that represent the diamters of interest for this case, and for this case we know the following info
Where and
We can begin finding this probability this probability
For this case they select a sample of n=79>30, so then we have enough evidence to use the central limit theorem and the distirbution for the sample mean can be approximated with:
And the best way to solve this problem is using the normal standard distribution and the z score given by:
And we can find the z scores for each limit and we got:
So we can find this probability:
And then since the interest is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.3 inches using the complement rule we got:
Answer:
1 - NORM.DIST(625, 600, 15 ,TRUE)
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In Excel:
We use the norm.dist command.
NORM.DIST(x, mean, standard_dev ,cumulative)
x is the tested value, mean and standard_dev are the mean and the standard deviation, while cumulative we use true to find a probability of a value lower than x, so for a value higher than x, we use:
1 - NORM.DIST(x, mean, standard_dev ,TRUE)
Mean of 600 copies and a standard deviation of 15 copies.
mean = 600, standard_dev = 15
You want to find the probability of selling more than 625 newspapers on any given day.
x = 625
What is the Excel Command
1 - NORM.DIST(625, 600, 15 ,TRUE)