All categories

2 years ago

I need help I need help I need help I need help I need help i need help I need help

Mathematics

1 answer:

beks73 [17]2 years ago

5 0

Answer:

5) The midrange is 19.5ºF

6) The midrange is 67.5º

Explanation:

The problem tell us how to calculate the midrange.

In (5) the minimum and maximum values are given (-6ºF and 45ºF, respectively). Using the formula:

$Midrange=\frac{-6+45}{2}=\frac{39}{2}=19.5ºF$

In (6), we need to find the minimum and maximum values from a list of them. We can see that the minimum is 58º and the maximum 77º

Then:

$Midrange=\frac{58+77}{2}=\frac{135}{2}=67.5º$

You might be interested in

In the diagram, the length of Line XY is ___.

Colt1911 [192]

The answer is: 24^2x-64x-24

5 0

3 years ago

Heather spend 2/7 of her money buying presents. she then had €48.65 left how much had she at first?

Kisachek [45]

Given :

Heather spend 2/7 of her money buying presents.

She then had €48.65 left.

To Find :

The initial amount of money she had.

Solution :

Let, initial amount she had is €x.

So,

$x - \dfrac{2x}{7} = 48.65\\\\\dfrac{5x}{7} = 48.65 \\\\x = \dfrac{48.65\times 7}{5}$

x = €68.11

Therefore, initially he had €68.11 .

3 0

3 years ago

2/1 = 8x - 2/ 9 ! help

bearhunter [10]

Answer: 5/2

Step-by-step explanation:

Cross multiply

18 = 8x - 2

20 = 8x

20/8 reduces to 5/2

7 0

3 years ago

Read 2 more answers

Can anyone help me with these question

Kazeer [188]

So hmm notice the picture below

a)

the center of the circle is the midpoint of those two folks

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -10}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{4-10}{2}\quad ,\quad \cfrac{6-2}{2} \right)\impliedby \textit{center of the circle}$

b)

the diameter is the distance between P and Q, or the length of that segment, and the radius is half the diameter

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -10}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 6}})
\end{array}\quad 
% distance value
d = \sqrt{({{ 4}}-{{ (-10)}})^2 + ({{ 6}}-{{ (-2)}})^2}
\\\\\\
d=\cfrac{\sqrt{(4+10)^2+(6+2)^2}}{2}\impliedby \textit{radius of the circle}$

c)

so, from a), you found the h,k coordinates for the center, from b) you've got the radius

so, just plug them in here then $\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}$

4 0

3 years ago

The cost C, in dollars, for advertising on a social networking website is proportional to the number n of clicks on the advertis

brilliants [131]

$ 45 is ur y value and 180 is ur x value....slope = y/x
so ur slope is : 45/180 = 0.25 or 1/4

7 0

3 years ago