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Elanso [62]
1 year ago
13

I need help I need help I need help I need help I need help i need help I need help

Mathematics
1 answer:
beks73 [17]1 year ago
5 0

Answer:

5) The midrange is 19.5ºF

6) The midrange is 67.5º

Explanation:

The problem tell us how to calculate the midrange.

In (5) the minimum and maximum values are given (-6ºF and 45ºF, respectively). Using the formula:

Midrange=\frac{-6+45}{2}=\frac{39}{2}=19.5ºF

In (6), we need to find the minimum and maximum values from a list of them. We can see that the minimum is 58º and the maximum 77º

Then:

Midrange=\frac{58+77}{2}=\frac{135}{2}=67.5º

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What is the length and the width of a rectangle with perimeter of 48 inches if its length is 7 inches longer than its width.
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Answer:

Length and the width of the rectangle is 15.5 inches and 8.5 inches respectively.

Step-by-step explanation:

Given:

Length = 7 inches + Width

=> P = 48 inches

=> L = (7 + W) inches............. (1)

Perimeter 'P' is the sum of all sides of the rectangle 2 (L + W)

∴ 48 inches = 2 (L + W) .................(2)

Substitute for L in equation (2)

∴ 48 inches = 2 [(7 + W) + W]

48 = 2[7 + 2W]

48 = 14 +4W

48 - 14 = 4W

34 = 4W

W = 8.5 inches

Recall that: Length, L = (7 + W)

∴ L = (7 + 8.5)

L = 15.5 inches

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