Select the correct answer.

Plz help im helping my brother :)

Tju [1.3M]

Answer:

B

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Simplify the expression 3x(x – 12x) + 3x2 – 2(x – 2)2. Which statements are true about the process and simplified product? Check

kirill115 [55]

Given: The algebraic expression 3x(x – 12x) + 3x² – 2(x – 2)² --------(i)

To prove: The final simplified product = –28x² +8x – 8.

Solution:

Step No. 1

First, we shall expand the term (x – 2)² by using Identity (a-b)²= a² + b² - 2ab

So, (x – 2)² = x² + 4 - 4x

From given expression (i)

3x(x – 12x) + 3x² – 2(x² + 4 - 4x) --------(ii)

Step No. 2

Now, we shall multiply by the terms within the parentheses in (ii)

(3x² – 36x²) + 3x² – (2x² + 8 - 8x) --------(iii)

Step No. 3

Now, we shall simplify the terms within the parentheses in (iii)

(– 33x²) + 3x² – (2x² + 8 - 8x) --------(iv)

Step No. 4

Now, we shall open the parentheses to eliminate parentheses in (iv)

– 33x² + 3x² – 2x² - 8 + 8x --------(v)

Step No. 5

Now, we shall add and subtract the like terms in (v)

– 28x² + 8x -8 --------(vi)

Hence, the simplified expression will be – 28x² + 8x -8

8 0

3 years ago

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Find the 10th partial sum of the arithmetic sequence defined by

Evgesh-ka [11]

Answer:

22.5

Step-by-step explanation:

If you expand the series, you can see the first few terms of the series:

Putting 1 in $n$ , $\frac{1}{2}(1)-\frac{1}{2}=0$
Putting 2 in $n$ , $\frac{1}{2}(2)-\frac{1}{2}=0.5$
Putting 3 in $n$ , $\frac{1}{2}(3)-\frac{1}{2}=1$
Putting 4 in $n$ , $\frac{1}{2}(4)-\frac{1}{2}=1.5$

We can see the series is 0, 0.5, 1, 1.5, ....

This is an arithmetic series with common difference (the difference in 2 terms) 0.5 and first term 0.

We know formula for sum of arithmetic series:

$s_{n}=\frac{n}{2}(2a+(n-1)d)$

Where,

$S_{n}$ denotes the nth partial sum
$a$ is the first term (in our case it is 0)
$n$ is the term (in our case it is 10 since we want to find 10th partial sum -- sum until first 10 terms)
$d$ is the common difference (difference in term and the previous term) (in our case it is 0.5)

Substituting these into the formula, we get the 10th partial sum to be:

$s_{10}=\frac{10}{2}(2(0)+(10-1)(0.5))\\s_{10}=5(0+(9)(0.5))\\s_{10}=5(0+4.5)\\s_{10}=5(4.5)\\s_{10}=22.5$

So the sum of the first 10 terms is 22.5. Third answer choice is right.

8 0

3 years ago

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Find the measures of the numbered angles.

Arte-miy333 [17]

1 = 90
2 = 65
3 = 65
4 = 25

90+25=115
180-115=65

have a merry christmas :)

3 0

2 years ago

Please help! acellus

ch4aika [34]

Answer:

The number that belongs in the green box is equal to 909.

General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem:
$\displaystyle a^2 + b^2 = c^2$

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify given variables.

a = 30

b = 3

c = x

Step 2: Find x

Let's solve for the general equation that allows us to find the hypotenuse:

[Pythagorean Theorem] Square root both sides [Equality Property]:
$\displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}$

Now that we have the formula to solve for the hypotenuse, let's figure out what x is equal to:

[Equation] Substitute in variables:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}$

∴ the hypotenuse length x is equal to √909 and the number under the square root, our answer, is equal to 909.

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Learn more about Trigonometry: brainly.com/question/27707750

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Topic: Trigonometry

3 0

2 years ago