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Pachacha [2.7K]
1 year ago
7

Write an equation for the line in point-slope form.Passing through (5,3) with x-intercept 6

Mathematics
1 answer:
Rama09 [41]1 year ago
3 0

Remember that the point-slope form of a line is:

y-k=m(x-h)

For a line with slope m and that passes through point (h,k)

Now, let's work on the line we're given. SInce the x-intercept is 6, we know that the line passes through (6,0).

Let's calculate the slope m :

m=\frac{3-0}{5-6}\rightarrow m=\frac{3}{-1}\Rightarrow m=-3

Now, using point (5,3) we can get the following point-slope form for the line:

y-3=-3(x-5)

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For both part A and part B, the cross-section would be a square.

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5 0
4 years ago
Can y'all help with this?
lesya692 [45]

Answer:

Step-by-step explanation:

rate = a

a = -16-(-11)/9-6

a= -5/3

3 0
3 years ago
A quadratic equation has x = -2 + 3i as a solution and passes through the point (-1, -15). Write the quadratic equation in stand
rosijanka [135]

Answer:

The standard form of the quadratic equation is f(x) = 2/3·(x + 2)² + 6

Step-by-step explanation:

The given solution of the quadratic equation is x = -2 + 3·i

A point on the path of the quadratic equation = (-1, -15)

The general form of the quadratic equation is f(x) = a·x² + b·x + c

When f(x) = 0, (At which the solution is found), we have x = -2 + 3·i

Substituting gives;

0 = a·(-2 + 3·i)² + b·(-2 + 3·i) + c

0 = 4·a - 12·a·i - 9·a - 2·b + 3·b·i + c

0 = 3·i·(b - 4·a) - 5·a - 2·b + c

∴ b = 4·a

c = 13·a

The general equation becomes

f(x) = a·x² + 4·a·x + 13·a

Also, when x = -1, f(x) = -15

f(-1) = -15 = a·(-1)² + 4·a·(-1) + 13·(-1)

-15 = a - 4·a - 13 = -3·a - 13

-3·a = -15 + 13 = -2

a = 2/3

The general form of the quadratic equation is therefore;

f(x) = 2/3·x² + 8/3·x + 13·2/3 = 2/3·x² + 8/3·x + 26/3

f(x) = 2/3·x² + 8/3·x + 26/3

The minimum value occurs at d(f(x)/dx = 0 = d(2/3·x² + 8/3·x + 13·2/3)/dx = 4/3·x + 8/3 = 0

x = -8/3 × 3/4 = -2

Therefore;

The minimum value of the quadratic function is f(-2) = 2/3·(-2)² + 8/3·(-2) + 13·2/3 = 6

The coordinates of the minimum point, which is the vertex point (h, k) = (-2, 6)

The standard form of the quadratic equation f(x) = a(x - h)² + k, is therefore;

f(x) = 2/3(x - (-2))² + 6 = 2/3·(x + 2)² + 6

f(x) = 2/3·(x + 2)² + 6

Also (h, k) can be gotten from h = -b/2a = -8/3/(2 × 2/3) = -2

k = c - b²/(4·a) = 26/3 - (8/3)²/(4 × 2/3) = 26/3 - 8/3 = 18/3 = 6

k = 6

The standard form of the quadratic equation f(x) = a(x - h)² + k becomes;

f(x) = 2/3·(x + 2)² + 6

6 0
3 years ago
A salesperson at a jewelry store earns 8% commission each week. Last week,Heidi sold $640 worth of jewelry. How much did the jew
DENIUS [597]

Answer:

19.2 your welcome my guy

Step-by-step explanation:

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8 0
3 years ago
Solve: 4^3x=4^2<br> I need help
Ipatiy [6.2K]

Answer: 2/3

Step-by-step explanation:

As the base of the two sides are equal, we can say that

3x = 2 which gives

x = 2/3

5 0
4 years ago
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