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3 years ago

1/4x+2=-4 how do you do this step by step?

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

Answer:

6.25 is the answer, I really dfon't know how to figure out which would be the procedure becuase I'm a little oxidated

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Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya would have bought 2

defon

Answer:

Option C

The student's conclusion is correct because the solution to the system of equations $3x+2y=27$ and $2x+y=16$ is $(5,6)$

Step-by-step explanation:

Let

x------> the cost of each burger

y-----> the cost of each sandwich

we know that

$3x+2y=27$ -----> equation A

$2x+y=(27-11)$

$2x+y=16$ ----> equation B

Solve the system of equations

Multiply the equation B by $-2$

$-2(2x+y)=-2*16$ -----> $-4x-2y=-32$ ------> equation C

Adds equation A and equation C

$3x+2y=27 \\-4x-2y=-32\\ ----------\\ 3x-4x=27-32\\ -x=-5\\x=5$

Substitute the value of x in the equation B

$2(5)+y=16$

$10+y=16$

$y=6$

The solution of the system of equations is the point $(5,6)$

The price of each burger is $\$5$

The price of each sandwich is $\$6$

6 0

2 years ago

Read 2 more answers

What is the missing term? (10x-4x^2)-(7x+?)=3x-6x^2

mafiozo [28]

The answer is 2x^2
Because everything on the right of the minus sign will turn negative

6 0

3 years ago

Read 2 more answers

Show work and explain with formulas.

Juli2301 [7.4K]

20 Answer: a₁ = 4

Step-by-step explanation:

$a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1$

21 Answer: n = 13

Step-by-step explanation:

$a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n$

22 Answer: n = 5

Step-by-step explanation:

$a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n$