Answer:
I believe your answer is minimum
All the numbers present in cubical dice = 6
- ( 1 , 2 , 3 , 4 , 5 ,6 ) <u>Total Outcomes = 6</u>
<u>Probability = Favorable outcomes / Total number of outcomes </u>
- Probability that 5 will come in first throw :-
<u>Favorable Outcomes = 1 </u>
<u>Favorable Outcomes = 1 Probability = 1/6</u>
- Probability that an odd number will come in second throw :-
<u>Favorable Outcomes = 3</u>
<u>Probability = 3/6 ; 1/2</u>
Answer:
I'm not sure but I got -16
Step-by-step explanation:
I just plugged in the -5 in place for the x
Fails the vertical line test at 2,3 and -1, 3
in return it is not a function