To solve this first find the area of each of the white shapes inside the rectangle
The formula for the area of a circle is:
A = πr²
In this case we know that the radius is 2
Plug what you know into the area of a circle formula:
A = π2²
A = π4
A = 4π
A ≈ 12.57
The formula for the area of a square is:
A = Length x Height
In this case we know that both length and height are 3
Plug what you know into the formula for area of a square:
A = 3 x 3
A = 9
To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):
12.57 + 9 ≈ 21.57
To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.
The formula for the area of a rectangle is:
A = Length x Height
The length is 10 and the height is 7
A = 10 x 7
A = 70
Shaded region:
70 - 21.57 = 48.43
Unshaded region: 21.57
Total area of surrounding rectangle: 70
Shaded region: 48.43
Hope this helped!
~Just a girl in love with Shawn Mendes
The second matrix ![\left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
represents the triangle dilated by a scale factor of 3.
Step-by-step explanation:
Step 1:
To calculate the scale factor for any dilation, we divide the coordinates after dilation by the same coordinated before dilation.
The coordinates of a vertice are represented in the column of the matrix. Since there are three vertices, there are 2 rows with 3 columns. The order of the matrices is 2 × 3.
Step 2:
If we form a matrix with the vertices (-2,0), (1,5), and (4,-8), we get
![\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D)
The scale factor is 3, so if we multiply the above matrix with 3 throughout, we will get the matrix that represents the vertices of the triangle after dilation.
Step 3:
The matrix that represents the triangle after dilation is given by
![3\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right] = \left[\begin{array}{ccc}3(-2)&3(1)&3(4)\\3(0)&3(5)&3(-8)\end{array}\right] = \left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%281%29%263%284%29%5C%5C3%280%29%263%285%29%263%28-8%29%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
This is the second option.
Answer:
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
6/2(1+2)
6/2(3)
6/6
1
Answer:
the answer is (12 +x)/5 please mark brainliest
