Answer:
Functions are linearly dependent (are not linearly independent.)
Step-by-step explanation:
Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation
is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.
Now, let f(x), g(x) and h(x) be the functions:

Then, letting α = 1, β= -1 and ω = -2, we see that:

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.