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kondor19780726 [428]
2 years ago
3

choose all the cylindrical containers that will hold at least 50 cm³ but not more than 55 cm³ of a liquid

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

Solution

For this case we can find the volume of each options and verify:

Case I

V=\pi\cdot(2)^2(4.1)=51.52

Case II

V=\pi\cdot(2.2)^2(3.2)=48.66

Case III

V=\pi\cdot(2.5)^2(2.7)=53.01

Case IV

V=\pi\cdot(2.1)^2(3.8)=52.64

Then the answer would be:

Case I: radius = 2cm and height = 4.1 cm

Case III: radius = 2.5 cm and height = 2.7 cm

Case IV: radius = 2.1 cm and height = 3.8 cm

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Alexxandr [17]

Answer:

La presión manométrica debe ser 6,272,000 Pa = 61.9 atm

Step-by-step explanation:

La presión absoluta se refiere al valor de presión referido al cero absoluto o al vacío, sin presión atmosférica. Es decir, la presión absoluta es la presión con respecto al vacío total.

La presión manométrica es la que ejerce un medio distinto al de la presión atmosférica y representa la diferencia entre la presión real o absoluta y la presión atmosférica. Es decir, la presión manométrica se mide en relación a la presión atmosférica y se define como la diferencia entre presión absoluta (Pabs) y presión atmosférica predominante (Patm). La presión manométrica sólo se aplica cuando la presión es superior a la atmosférica.  

Entonces,  Pmanometrica = Pabs – Pamb

Para encontrar la presión a una profundidad h en un líquido sin movimiento, expuesto al aire cerca de la superficie de la Tierra, la presión manométrica puede ser calculada mediante:

Pmanometrica=ρ*g*Δh

donde ρ es la densidad del fluido, g la gravedad y Δh la variación en la altura.

En este caso:

  • ρ=1000 \frac{kg}{m^{3} } (densidad del agua)
  • g= 9.8  \frac{m}{s^{2} }
  • Δh=hfinal - hinitial= 1370 m - 730 m= 640 m

Reemplazando:

Pmanometrica=  1000 \frac{kg}{m^{3} } *9.8 \frac{m}{s^{2} } * 640 m

Resolviendo:

Pmanometrica= <u><em>6,272,000 Pa = 61.9 atm</em></u> (siendo 1 pascal = 9.869*10⁻⁶ atmósferas )

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