Question

Use Special Right Triangles to solve for the value of y. Leave your answer in SIMPLIFIED radical form.

Answer 1

We can use the sine function and tangent function in order to solve for x and y:

$\begin{gathered} sin(\theta)=\frac{opposite}{hypotenuse} \\ sin(60)=\frac{15}{x} \\ x=\frac{15}{sin(60)} \\ x=10\sqrt{3} \end{gathered}$$\begin{gathered} tan(\theta)=\frac{opposite}{adjacent} \\ tan(60)=\frac{15}{y} \\ y=\frac{15}{tan(60)} \\ y=5\sqrt{3} \end{gathered}$