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Basile [38]
1 year ago
12

Use Special Right Triangles to solve for the value of y. Leave your answer in SIMPLIFIED radical form.

Mathematics
1 answer:
Scorpion4ik [409]1 year ago
7 0

We can use the sine function and tangent function in order to solve for x and y:

\begin{gathered} sin(\theta)=\frac{opposite}{hypotenuse} \\ sin(60)=\frac{15}{x} \\ x=\frac{15}{sin(60)} \\ x=10\sqrt{3} \end{gathered}\begin{gathered} tan(\theta)=\frac{opposite}{adjacent} \\ tan(60)=\frac{15}{y} \\ y=\frac{15}{tan(60)} \\ y=5\sqrt{3} \end{gathered}

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Help me on number problem 3 please !
Elenna [48]

Answer:  x-intercept :12 & y-intercept ;-8


Step-by-step explanation:To find the x-intercept ,substitute in 0 for y and solve for x .

8x-12y=96

8x-12(0)=96

8x=96 (divide both # by 8)

x=12

To find the y-intercept ,substitute in 0 for x and solve for y .

8(0)-12y=96

-12y=96(Divide by -12 both )

y=-8


6 0
3 years ago
Pls help!! I need to finish this until Friday if not u know.... Trouble
Lena [83]
If she is cutting the chain into 32 pieces a foot each, she has 32 pieces of chain.
7 0
3 years ago
Hi.
NeX [460]

Answer:

(a)

1 sig: 0.005

2 sig: 0.0048

3 sig: 0.00482

(b)

1 sig: 50

2 sig: 50.

3 sig: 50.0

(c)

1 sig: 0.0010

2 sig: 0.00098

3 sig: 0.000981

Step-by-step explanation:

Significant Figures Rules:

  1. Any non-zero digit is significant.
  2. Any trailing zeros after the decimal is significant.
  3. Any zeros between 2 significant digits are significant.
  4. Zeroes before significant numbers in the decimal place are NOT significant; they are placeholders.

(a)

0.004816 - the zeros are placeholders, so they do not count as sig figs.

(b)

50.00168 - the zeros are between 2 significant figures, so they do count as sig figs.

(c)

0.0009812 - the zeros are placeholders, so they do not count as sig figs

5 0
3 years ago
What is the length of the altitude of the equilateral triangle below
ale4655 [162]
Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3)                        But sin60° = √3/2

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3 = 9

Option E.

Hope this helps.
4 0
3 years ago
A 13ft board is to be cut into three pieces, two equal length ones and the third 9in shorter than each of the other two. If cutt
vaieri [72.5K]

Answer:

The pieces are 55 inches, 55 inches and 46 inches long

Step-by-step explanation:

A 13ft board is to be cut into three pieces consisting of two equal length ones. The third one is 9in shorter than each of the other two.

Let us first convert the length of the board to inches:

1 ft = 12 inches

13 ft = 12 * 13 = 156 inches

Let the length of each of the other two pieces be x.

Therefore, the length of the third piece is (x - 9)

Therefore, the sum of the lengths of the three pieces is equal to 156 inches. This means that:

x + x + (x - 9) = 156

x + x + x - 9 = 156

=> 3x = 156 + 9

3x = 165

x = 165 / 3 = 55 inches

Each of the first two pieces are 55 inches long.

The length of the third piece will be:

55 - 9 = 46 inches

The pieces are 55 inches, 55 inches and 46 inches long.

4 0
3 years ago
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