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velikii [3]
3 years ago
10

What is 3186 divided by 62

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0
It is 51.38 hope that helps
lora16 [44]3 years ago
3 0
51.38 that's the answer
You might be interested in
Write 0.00109 ounces in scientific notation
jasenka [17]
Here is the answer.
You gotta move to the right 3 times

4 0
3 years ago
"Durable press" cotton fabrics are treated to improve their recovery from wrinkles after washing "Wrinkle recovery angle" measur
ludmilkaskok [199]

Answer:

At 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

a)

X[bar]₁= 120.8 degrees

X[bar]₂= 162.75 degrees

b)

S₁²= 14.5155 degrees

S₂²= 24.4727 degrees

Step-by-step explanation:

Hello!

The study variable is X: wrinkle recovery angle for a fabric specimen.

There is a suspicion that there is a difference in recovery from wrinkles after washing between two products (Permafresh and Hilite). To test this suspicion two random samples of fabric, 5 were treated with Permafresh and 4 were treated with Hylite resulting in the data:

Sample 1 (Permafresh)

X₁: wrinkle recovery angle for a fabric specimen treated with Permafresh.

X₁~N(μ₁;σ₁²)

n₁= 5

124; 104; 142; 111; 123

Sample mean X[bar]₁= (∑x₁i)/n₁= 604/5= 120.8 degrees

Sample variance S₁²= \frac{1}{(n₁-1)}[(∑x₁²i)-(∑x₁i)²/n₁] = \frac{1}{4}[(73806)-(604)²/5]= 210.7 degrees²

S₁= 14.515 ≅ 14.52 degrees

Sample 2 (Hylite)

X₂: wrinkle recovery angre for a fabric specimen trated with Hylite.

X₂~N(μ₂;σ₂²)

n₂= 4

147; 199; 149; 156

Sample mean X[bar]₂= (∑x₂i)/n₂= 651/4= 162.75 degrees

Sample variance S₂²= \frac{1}{(n₂-1)}[(∑x₂²i)-(∑x₂i)²/n₂] = \frac{1}{3}[(107747)-(651)²/4]= 598.916 ≅ 598.92 degrees²

S₂= 24.472≅ 24.47 degrees

To test the suspicion that there is a difference between the winkle recovery angle on fabric samples treated with Permafresh and Hylite, the hypothesis is:

H₀: μ₁ = μ₂

H₁: μ₁ ≠ μ₂

α: 0.05

To test the difference between the population means, considering that only sample information is available and the size of both samples, the most appropriate statistic to use is a pooled t for independent samples (unknown but equal population variances):

t=<u> (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) </u>~t_{n_1+n_2-2}

                Sa√(1/n₁+1/n₂)

Sa²= <u> (n₁-1)S₁² + (n₂-1)S₂² </u> = <u> (4*210.7)+(3*598.92) </u>= 377.08

                n₁ + n₂ - 2                     5+4-2

Sa= 19.418≅ 19.42

t=<u> (X[bar]₁ - X[bar]₂) - (μ₁ - μ₂) </u>=  <u>  (120.8-162.75) - 0 </u>= -3.22

                Sa√(1/n₁+1/n₂)                19.42√(1/5+1/4)    

Using the critical region approach, this rejection region is two-tailed with critical values:

t_{n_1+n_2-2; \alpha/2 } = t_{7; 0.025 } = -2.365

t_{n_1+n_2-2; 1- \alpha/2 } = t_{7; 0.975 } = 2.365

If t ≤ -2.365 or t ≥2.365, then the decision is to reject the null hypothesis.

If -2.365 < t < 2.365, then the decision is to not reject the null hypothesis.

Since the calculated t-value is less than the left critical value, the decision is to reject the null hypothesis.

I've calculated the p-value for the test: 0.0146

This p-value is less than the significance level of 0.05, then, using this approach, the decision is also to reject the null hypothesis.

This means, that at 5% there is significant evidence to reject the null hypothesis. You can conclude that there is a difference between the population mean of the wrinkle recovery angle of fabric treated with Permafresh and the population mean of the wrinkle recovery angle of fabric treated with Hylite.

I hope it helps!

4 0
4 years ago
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
3 years ago
The relation shown in the graph is a function. true or false​
exis [7]

Answer:

true.

Step-by-step explanation:

the line only passes through the y-intercept once.

6 0
3 years ago
What is the biggest squime
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The largest squime is 25973641
8 0
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