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dimulka [17.4K]
1 year ago
5

In quadrilateral BADC, AB = AD and

Mathematics
1 answer:
zzz [600]1 year ago
8 0

The quadrilateral BADC. AB = AD and BC = DC.

1.The AC and BD lines are perpendicular lines.

2.∠ACB = ∠ACD

Given that,

AB = AD and BC = DC in the quadrilateral BADC. This quadrilateral's symmetry line is the line AC.

1. We have to find how  the diagonals AC and BD are perpendicular.

In the figure we can see the BADC quadrilateral and the lines AC and BD.

To prove they are perpendicular we have to prove that they have 90° all angles.

∠AOD is 90°.

∠AOB is 90°.

∠BOC is 90°.

∠DOC is 90°.

Therefore, we can say that AC and BD are perpendicular lines.

2.We have to find the angles ABC and ADC have same angles.

The BADC quadrilateral

AB= AD

BC= DC

This quadrilateral's symmetry line is AC.

Think about the triangles BAC and DAC.

These triangles contain

AB = AD

BC = DC

AC = AC - reflexive property

So, the SSS postulate of ΔBAC ≅ ΔDAC

Congruent triangles have comparable sides and angles that are also congruent, so ∠ACB = ∠ACD

Another concept: The line that separates the figure into two identical figures is the line of symmetry. As a result, ΔBAC and ΔDAC share the same properties (are congruent) and have the same corresponding sides and angles.

To learn more about quadrilateral visit: brainly.com/question/13805601

#SPJ1

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What’s the correct answer for this question?
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3 0
3 years ago
A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in
salantis [7]
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C                                      ⇒A-B-C=0
28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1             1              1               55,000
1            -1            -1                         0
28         16           12          1,158,000 


1             1              1               55,000
0            -2             -2             -55,000                                    (R₂-R₁)
0           12             16           382,000                                    (28R₁-R₂) 


1            1                1              55,000
0           -2              -2             -55,000
0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000


-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
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