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Oliga [24]
2 years ago
4

a manufacturing machine has a 5% defect rate. if 7 items are chosen at random, what is the probability that at least one will ha

ve a defect?
Mathematics
1 answer:
ioda2 years ago
6 0

The probability of selecting at least one defective item at random is 0.3017.

The probability of an event occurring at least once will be calculated as the complement of the probability of the event never occurring. You can use exponents to multiply the number of events that occurred when calculating this amount.

Defect rate = P(defect) = 0.05

Probability is defined as the required outcome divided by the total number of possible outcomes.

P( at least 1 is defective) = 1 - P(none is defective)

P(not defective) = 1 - P(defective) = 1 - 0.05 = 0.95

P(none is defective) = P(non defective)^7

P(none defective) = 0.95× 0.95 × 0.95 × 0.95 × 0.95× 0.95× 0.95=0.6983

P(at least one is defective) = 1 - 0.6983 = 0.3017

Therefore, probability of at least one defective item is 0.3017.

For more information on Probability, visit :

brainly.com/question/11443428

#SPJ4

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Deepak is a landscaper who charges $30 for each job he does plus an additional $15 for each hour he works. He only accepts jobs
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Hey there! I'm happy to help!

The only thing we have to do is solve our inequality to find the answer!

30+15x ≥ 90

We subtract 30 from both sides.

15x ≥ 60

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x ≥ 4

Therefore, Deepak can only accept jobs that last 4 or more hours.

I hope that this helps! Have a wonderful day!

3 0
3 years ago
Read 2 more answers
The force acting on a beam was measured 5 times under the same operating conditions. This process was repeated by 3 observers, r
Akimi4 [234]

Answer:

The Pooled Standard Deviation for these data sets is 1.09

Step-by-step explanation:  

Given that;

Standard Deviation 1 = 1.11

Standard Deviation 2 = 0.99

Standard Deviation 3 = 1.15

pooled standard deviation is given as;

S_{pooled} = (n1 - 1 )s1² + ..... + ( nk - 1 )sk² / n1 + ..... + nk - 1

where n1, n2....., nk are the sample sizes of k groups and s1, s2, ....., sk are the standard deviations of k groups respectively

so for the 3 groups;

S_{pooled}² =   (n1 - 1 )s1² + (n2 - 1 )s2² + ( n3 - 1)s3² / n1 + n2 + n3 - 3

we substitute

S_{pooled}² =   (5 - 1 )1.11² + (5 - 1 )0.99 ² + ( 5 - 1)1.15² / 5 + 5 + 5 - 3

S_{pooled}² =   (4.9284 + 3.9204 + 5.29) / 12

S_{pooled}² =   14.1388 / 12

S_{pooled}² =   1.1782

S_{pooled} = √1.1782

S_{pooled} = 1.08544 ≈ 1.09

Therefore, The Pooled Standard Deviation for these data sets is 1.09

6 0
3 years ago
Simplify : 5y-2y+4=10​
Mnenie [13.5K]
Answer:

See below.

Step-by-step explanation:

5y - 2y + 4 = 10

5y - 2y = 6

3y = 6

y = 2

Check:

5y - 2y + 4 = 10

5(2) - 2(2) + 4 = 10

10 - 4 + 4 = 10

6 + 4 = 10

10 = 10

The value of y = 2
7 0
3 years ago
Read 2 more answers
This figure is made up of a rectangle and parallelogram.<br> What is the area of this figure?
kondaur [170]

Answer:

51 square units

Step-by-step explanation:

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⇒ area = 4 x 3 = 12 square units

Area of a rectangle = width x length

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length = √(9² + 6²) = √117

area = √13 x √117 = 39 square units

Total area = 12 + 39 = 51 square units

8 0
3 years ago
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