Answer:
about 0.177 mg/mL
Step-by-step explanation:
The maximum is found where the derivative of C(t) is zero.
dC/dt = 1.35e^(-2.802t) -(1.35t)2.802e^(-2.802t) = 0
Solving for t gives ...
t = 1/2.802
So, the maximum C(t) is ...
C(1/2.802) = 1.35/2.802e^(-1) ≈ 0.177 . . . . . mg/mL
The maximum average BAC during the first 6 hours is about 0.177 mg/mL.
_____
The maximum occurs about 21 minutes 25 seconds after consumption.
Answer:
the answer is 7 i believe
Answer:
Apple
Orange
Step-by-step explanation:
Apple has the greater median with a median value of 150 which is more than that of orange at 130
The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.
Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.
No it isn’t correct, it’s the second one! Good luck!