Question

if f: a-->b be defined by y = f(x) =x^2-2 and same function defined in the set of ordered pair form is {(2,....),(3,..),(.....,14)(....,-1), find the missing components of the ordered pairs

Answer 1

Answer:

The ordered pairs are(missing values in original question are underlined)

(2, 2), (3, 7), (-4,14),(4,14), (-1,-1),(1,-1)

Step-by-step explanation:

The given function is $y=x^{2}-2$

In the first two ordered pairs we are given the value of $x$ and all we have to do is substitute for $x$ in the above function and solve for $y$

So, for (2,...) where $x=2,$

$y=2^{2}2-2=4-2=\boldsymbol{2}$

For the second pair, (3,...)

$y=3^{2}-2=9-2=\boldsymbol{7}$

For the last two pairs, we are given what the y value is and we substitute for y in the function equation and solve for x

For (..., 14) we get

14=x^{2}-2==>16=x^{2},so x=\pm4. This means the two possible values for x are -4 and 4

For the last pair, y=-1 which gives us

$-1=x^{2}-2== > (-1)-(-2)=x^{2}$

which gives the two possible values for x as $x=\boldsymbol{-1}$ and $x=\bold{1}$

See the attached image for a visual depiction of these points